output method has no effect here

ID:139208
 
Apr 30 2011, 7:11 am
Code:
So I have this variable under a type:
var/mob/mechanism/linkable/link

And I have this proc (both under the same type):
                stepped_on(mob/m)
                    if(link)
                        var/mob/mechanism/linkable/linked = link
                        linked.activate(m)
//link.activate(m)


Problem description:

For whatever reason, I can't use the commented-out version, but I can typecast it and it works fine. I suppose this isn't really a problem, just more of a question as to what this means, for future reference.

Apr 30 2011, 7:30 am
Is it compiler error, runtime error, or just code doesn't do anything?
Apr 30 2011, 7:31 am
In response to Zaoshi
It's a compiler error.
Apr 30 2011, 7:33 am
In response to DivineTraveller
Being able to see the error helps too :)
Maybe : operator works, instead of . ?
Apr 30 2011, 7:35 am
In response to Zaoshi
The title is the error:
code\mechanisms.dm:42:error: link: output method has no effect here

(line 42 points to the un-cast reference)
No, the colon does not work, and I'd rather do the typecasting than use the colon anyway.
Apr 30 2011, 6:23 pm
In response to DivineTraveller
Appears there is built-in proc link(). I guess it thinks you call proc, not access object.
Apr 30 2011, 11:23 pm
In response to Zaoshi
Turns out that was the issue. To think, I had contemplated calling my variable 'linked' earlier anyway. Thanks!
May 1 2011, 2:46 pm
In response to DivineTraveller
You can use src.link.activate(m)