a timing problem

ID:149396
 
May 9 2002, 9:56 am (Edited on May 10 2002, 8:35 am)
i decided to change it down, is there a way to stop a radomly moving mob after 'X' number of steps

this is my code so far...

mob
mob
icon = 'mob.dmi'
icon_state = "walking"
New()
..()
LCycle1()

mob
proc
LCycle1()
if(client)
return
step_rand(src)
spawn(7)
world << "[src] is at '[x], [y]!'"
spawn(7) LCycle1()

(>=1 tab) any suggestions would be helpfull!
May 10 2002, 8:00 am
i could realy use some help with this... thanks
May 10 2002, 9:29 am
Setup something with a for loop (They're a bit complicated if you're new, so be sure to look them up first.)

<code>mob/proc/TimedMove(times, delay) for(var/move=times, times>0, times--) sleep(delay) step_rand(src) return</code>

When you activate this for a mob like this:

<code>mob/New() spawn() src.TimedMove(10,10)</code>

Where "times" in the proc above is the number of times you want them to move, and "delay" is the number of ticks you want to pass by before each move; then the mob will actively move about randomly after every "delay" period passes, until the number of times you told it to move experies at which point the proc will terminate.

Does that make sense?
May 10 2002, 9:55 am
In response to Foomer
yeah thanks