prob() question

ID:177614
 
Aug 19 2002, 1:11 pm
For this exercise, assume the usr's var "bonusaccuracy" is equal to 5.

Would if(prob((25)+(usr.bonusaccuracy))) be the same as if(prob(30))?

If not, what would be a way to achieve a system like this?
Aug 19 2002, 1:23 pm
yes, it's the same, but you don't need all the extra parenthesis ((25), (usr.bonusaccuracy)).
Aug 19 2002, 1:33 pm (Edited on Aug 19 2002, 1:53 pm)
In response to Garthor
Thanks for the quick response. However, I'll put all the parentheses I want on them.

[Update]
I just attempted this in my test game, and the prob() doesn't seem to be doing anything, since when I attack something, there is no result.
[Update 2]
Seems it was a bit of poor indenting on my part. Problem fixed.
Aug 19 2002, 8:23 pm
In response to Mertek
prob() only returns true if the probability is hit. A 30% probability probably doesn't hit too often. Try upping it to like 80 or some other high number for testing and see if you get a result then.
Aug 20 2002, 4:22 am
In response to Mertek
Try if(prob(25+that_bonus))

prob(number) returns true or false.

Alathon\\
Aug 20 2002, 7:12 am
In response to sapphiremagus
I am aware of that. I noticed that when you had a weapon equipped, it added the chance of not hitting, when I wanted it to subtract. Fixed it and it worked fine.