ID:184163
 
Let n be an integer. Show that, if 2 + 2*sqrt(1 + 12n^2) is an integer, then it is a perfect square number.

Not that one'd help, but no calculators allowed.

sqrt() = square root by the way.

If you're confused about my notation, I'm saying "Show that, if 2 plus 2 times the square root of (1 + 12n squared) is an integer, then it is a perfect square number".

And no, you can't just say "Let n = 2. Then 2 + 2*sqrt(1+12*2^2) = 16". You have to prove it for n.
The sqaure root formulae?
Won't that work?
In response to Nishiatsu
What?
mob/verb/Solve_Math(n as num)
if(2 + 2*sqrt(1 + 12*n**2))
world<<"[n] is a perfect square number."


;]
In response to Airjoe
That doesn't even work. Let n = 3.
In response to Abhishake
Abhishake wrote:
That doesn't even work. Let n = 3.

3 is not a perfect square
In response to Shlaklava
The question means that if 2 + sqrt(1 + 12n^2) is an integer, 2 + sqrt(1+12n^2) is a perfect square.

And to Airjoe I was showing his code wouldn't work when n = 3.