If the grid is visible, do this. If it's not, do this instead. How? in Developer Help

ID:556065
 
Mar 20 2012, 12:19 pm
(See the best response by Kaiochao.)
Another simple question that I could probably find the answer to in an interface demo... But I would rather just post it here.

So, how do you use an if statement to check if an interface grid is visible?
#1 Mar 20 2012, 12:26 pm
Best response
One way would be to use an actual variable that you set when you make grids visible or invisible.
mob
    var grid_is_visible
    proc
        hide_grid()
            if(grid_is_visible)
                grid_is_visible = 0
                winshow(src, "grid", 0)

        show_grid()
            if(grid_is_visible) return
            grid_is_visible = 1
            winshow(src, "grid")

        toggle_grid() grid_is_visible ? hide_grid() : show_grid()



The other way, which is a much more straightforward solution to your painfully simple question, is to use winget().
var is_visible = winget(src, "grid_id", "is-visible")
if(is_visible == "true")
    return TRUE
else return FALSE
#2 Mar 20 2012, 12:28 pm
Awesome! Thanks for putting up with me, Kaio. :D